(x^-1y^1/2)^-1/3/x^1/5y^-1/2

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Solution for (x^-1y^1/2)^-1/3/x^1/5y^-1/2 equation: 


D( x )

x^1 = 0

x = 0

(x^-1*y^1)/2 = 0

x^1 = 0

x^1 = 0

x = 0

x = 0

x = 0

(x^-1*y^1)/2 = 0

(x^-1*y^1)/2 = 0

(x^-1*y)/2 = 0

1/2*x^-1*y = 0 // : 1/2*y

x^-1 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

(((((((x^-1*y^1)/2)^-1)/3)/(x^1))/5)*y^-1)/2 = 0

(((((((x^-1*y)/2)^-1)/3)/x)/5)*y^-1)/2 = 0

1/15*y^-2 = 0

x naleu017Cy do R

x in (-oo:0) U (0:+oo)

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